A baseball player swings and connects with a pitch. The equation $H=-16 t^{2}+80 t+4$ represents the height of the ball (in feet) above the ground after $t$ seconds.
Determine the height of the ball after 1.1 seconds. Do not round your result.
The height of the ball after 1.1 seconds is
Answer
Final Answer: The height of the ball after 1.1 seconds is \(\boxed{72.64}\) feet.
Step 1 ：The problem provides the equation \(H=-16 t^{2}+80 t+4\) which represents the height of the ball (in feet) above the ground after \(t\) seconds.
Step 2 ：We are asked to determine the height of the ball after 1.1 seconds. This can be found by substituting \(t=1.1\) into the equation.
Step 3 ：Substituting \(t=1.1\) into the equation gives us \(H=-16*(1.1)^{2}+80*(1.1)+4\).
Step 4 ：Solving the equation gives us \(H=72.64\).
Step 5 ：Final Answer: The height of the ball after 1.1 seconds is \(\boxed{72.64}\) feet.
