Determine the remaining sides and angles of the triangle $A B C$.
\[
A=120.65^{\circ}, C=33.28^{\circ}, c=100
\]
\[
B=26.07^{\circ}
\]
\[
a \approx
\]
(Do not round until the final answer. Then round to the nearest tenth as needed.)

Step 1 ：We are given that in triangle ABC, \(A=120.65^{\circ}\), \(C=33.28^{\circ}\), and \(c=100\).

Step 2 ：We know that the sum of the angles in a triangle is 180 degrees. So we can calculate angle B by subtracting angles A and C from 180. This gives us \(B=180-120.65-33.28=26.07^{\circ}\).

Step 3 ：We can use the law of sines to find the lengths of sides a and b. The law of sines states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all three sides of the triangle.

Step 4 ：We can set up the following equations to find a and b: \(a = \frac{c \cdot \sin(A)}{\sin(C)}\) and \(b = \frac{c \cdot \sin(B)}{\sin(C)}\).

Step 5 ：Substituting the given values into these equations, we get \(a \approx 156.8\) and \(b \approx 80.1\).

Step 6 ：\(\boxed{\text{Final Answer: The remaining sides of the triangle are } a \approx 156.8 \text{ and } b \approx 80.1}\)