What angle does the line $y=\sqrt{3} \cdot x+1$ make with the positive side of the line $y=1$ ?
$\theta=$
(Type your answer in degrees.)

Step 1 ：The angle between two lines with slopes m1 and m2 is given by the formula: \(\tan(\theta) = \frac{|m2 - m1|}{1 + m1*m2}\)

Step 2 ：Here, the slope of the line \(y = \sqrt{3}*x + 1\) is \(\sqrt{3}\) and the slope of the line \(y = 1\) is 0. So, we can substitute these values into the formula to find the angle.

Step 3 ：Substituting the values we get: \(m1 = 1.7320508075688772\), \(m2 = 0\), \(\theta_{rad} = 1.0471975511965976\), \(\theta_{deg} = 59.99999999999999\)

Step 4 ：Final Answer: The angle that the line \(y=\sqrt{3} \cdot x+1\) makes with the positive side of the line \(y=1\) is approximately \(\boxed{60}\) degrees.