Sans Serif
$=14 \mathrm{px} \quad=1.5 \mathrm{pt}=\mathrm{B} I \underline{\mathrm{U}} S \underline{\mathrm{A}}$
$14-$
1. What is the length of the crust in John's slice?
\[
\begin{array}{l}
3.14159 \times 16=50.27 \text { inches } \\
360 / 8=45 \text { degrees } \\
45 / 360 \times 50.265=5.029=5.03 \text { inches }
\end{array}
\]
2. What is the area of John's slice?
$16 / 2=8$ inches
$3.14159 \times 64=201.02$ inches
$36 / 360=0.11 / 10 \times 201.06=20.11$ inches
3. What is the length of the crust in Susan's slice?
Answer
Final Answer: The length of the crust in John's slice is approximately \(\boxed{12.57}\) inches.
Step 1 ：The pizza is assumed to be a perfect circle with a radius of 16 inches.
Step 2 ：The slice John has is 1/8th of the pizza, or 45 degrees of the circle.
Step 3 ：The circumference of the circle is given by the formula \(2 \pi \times \text{radius}\).
Step 4 ：The length of the crust on John's slice would be 1/8th of the total circumference.
Step 5 ：Calculate the circumference: \(2 \pi \times 16 = 100.53\) inches.
Step 6 ：Calculate the length of the crust: \(\frac{1}{8} \times 100.53 = 12.57\) inches.
Step 7 ：Final Answer: The length of the crust in John's slice is approximately \(\boxed{12.57}\) inches.
