Solve the system by graphing.
\[
\begin{array}{r}
3 x+y=3 \\
x-y=1
\end{array}
\]
Use the graphing tool to graph the system.
Thus, the solution to the system of equations is \(\boxed{(1, 0)}\).
Step 1 :First, we rewrite the equations in slope-intercept form (y = mx + b). The first equation becomes \(y = -3x + 3\), and the second equation becomes \(y = x - 1\).
Step 2 :We then graph these two lines. The first line has a slope of -3 and a y-intercept of 3. The second line has a slope of 1 and a y-intercept of -1.
Step 3 :The solution to the system of equations is the point where the two lines intersect. By observing the graph, we can see that the two lines intersect at the point (1, 0).
Step 4 :Thus, the solution to the system of equations is \(\boxed{(1, 0)}\).