If the $2^{\text {nd }}$ term of an arithmetic sequence is 10 and the $7^{\text {th }}$ term is 35 , find the $11^{\text {th }}$ term.

Step 1 ：Given that the second term of an arithmetic sequence is 10 and the seventh term is 35, we need to find the 11th term.

Step 2 ：First, we find the common difference of the arithmetic sequence. The common difference is the difference between any two successive terms. We can find it by subtracting the second term from the seventh term and then dividing by the number of terms between them. So, \(d = \frac{{35 - 10}}{{7 - 2}} = 5.0\)

Step 3 ：Next, we find the 11th term by adding the common difference to the 10th term. The 10th term can be found by adding the common difference to the 9th term, and so on. So, the 11th term is \(10 + 5.0 \times (11 - 2) = 55.0\)

Step 4 ：Final Answer: The 11th term of the arithmetic sequence is \(\boxed{55}\)