The exposure index EI for a 35 millimeter camera is a measurement of the amount of light that hits the film. It is determined by the equation $E I=\log _{2}\left(\frac{f^{2}}{t}\right)$, where $f$ is the "f-stop" setting on the camera, and $t$ is the exposure time in seconds. Suppose the $f$-stop setting is 4 and the desired exposure time is 2 seconds. What will the resulting exposure index be? $E I=$
Answer
Final Answer: The resulting exposure index will be \(\boxed{3.0}\).
Step 1 ：Given that the f-stop setting (f) is 4 and the exposure time (t) is 2 seconds, we can substitute these values into the formula for the exposure index (EI).
Step 2 ：The formula for the exposure index is \(E I=\log _{2}\left(\frac{f^{2}}{t}\right)\).
Step 3 ：Substituting the given values, we get \(E I=\log _{2}\left(\frac{4^{2}}{2}\right)\).
Step 4 ：Solving this, we find that the exposure index (EI) is 3.0.
Step 5 ：Final Answer: The resulting exposure index will be \(\boxed{3.0}\).
