$\int \frac{x-1}{x^{2}} d x$
Final Answer: \(\boxed{\log(x) + \frac{1}{x}}\)
Step 1 :This is a problem of integral calculus. The integral is of a rational function.
Step 2 :We can simplify the integrand by dividing each term in the numerator by \(x^{2}\), which will make it easier to integrate.
Step 3 :The integral of the function \(\frac{x-1}{x^{2}}\) is \(\log(x) + \frac{1}{x}\).
Step 4 :Final Answer: \(\boxed{\log(x) + \frac{1}{x}}\)