Problem

(1 point) Let b1=[13] and b2=[38]. The set B={b1,b2} is a basis for R2. Let T:R2R2 be a linear transformation such that T(b1)=2b1+6b2 and T(b2)=2b1+2b2.
(a) The matrix of T relative to the basis B is
(b) The matrix of T relative to the standard basis E for R2 is

Answer

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Answer

To find the matrix of T relative to the standard basis E for R2, we express the images of the standard basis vectors under T as linear combinations of the standard basis vectors. The coefficients of these linear combinations form the entries of the matrix. For T(e1), the coefficients are 16 and -42, and for T(e2), the coefficients are 4 and -10. Therefore, the matrix of T relative to the standard basis E for R2 is [1644210].

Steps

Step 1 :Given the basis vectors b1=[13] and b2=[38] for R2, and the linear transformation T such that T(b1)=2b1+6b2 and T(b2)=2b1+2b2.

Step 2 :To find the matrix of T relative to the basis B, we express the images of the basis vectors under T as linear combinations of the basis vectors. The coefficients of these linear combinations form the entries of the matrix. For T(b1), the coefficients are 2 and 6, and for T(b2), the coefficients are 2 and 2. Therefore, the matrix of T relative to the basis B is [2262].

Step 3 :To find the matrix of T relative to the standard basis E for R2, we express the images of the standard basis vectors under T as linear combinations of the standard basis vectors. The coefficients of these linear combinations form the entries of the matrix. For T(e1), the coefficients are 16 and -42, and for T(e2), the coefficients are 4 and -10. Therefore, the matrix of T relative to the standard basis E for R2 is [1644210].

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