Problem

$x$ varies directly as $p$. If $x=32$ when $p=16$, find $x$ when $p$ is 20 .
\[
x=
\]

Answer

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Answer

Final Answer: \(\boxed{40}\)

Steps

Step 1 :The problem states that $x$ varies directly as $p$. This means that $x$ and $p$ are directly proportional to each other. The formula for direct variation is $x = kp$, where $k$ is the constant of variation.

Step 2 :We can find the value of $k$ using the given values of $x$ and $p$. Given that $x=32$ when $p=16$, we can substitute these values into the formula to get $32 = k*16$. Solving for $k$ gives us $k = 2.0$.

Step 3 :Now that we have the value of $k$, we can find the value of $x$ when $p$ is 20. Substituting these values into the formula gives us $x = 2.0*20$.

Step 4 :Solving for $x$ gives us $x = 40.0$.

Step 5 :Final Answer: \(\boxed{40}\)

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