Given the function $f$, find $f(-3), f(3), f(-a),-f(a), f(a+h)$.
\[
f(x)=2 x-7
\]
\[
f(-3)=
\]
\[
f(3)=
\]
\[
\begin{aligned}
f(-a) & =\square \\
-f(a) & =\square \\
f(a+h) & =\square
\end{aligned}
\]

Answer

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Answer

Substitute $x=a+h$ into the function $f(x)=2x-7$, we get $f(a+h)=2(a+h)-7=2a+2h-7$

Steps

Step 1 ：Substitute $x=-3$ into the function $f(x)=2x-7$, we get $f(-3)=2(-3)-7=-6-7=-13$

Step 2 ：Substitute $x=3$ into the function $f(x)=2x-7$, we get $f(3)=2(3)-7=6-7=-1$

Step 3 ：Substitute $x=-a$ into the function $f(x)=2x-7$, we get $f(-a)=2(-a)-7=-2a-7$

Step 4 ：Substitute $x=a$ into the function $f(x)=2x-7$, we get $f(a)=2a-7$, then multiply by $-1$, we get $-f(a)=-2a+7$

Step 5 ：Substitute $x=a+h$ into the function $f(x)=2x-7$, we get $f(a+h)=2(a+h)-7=2a+2h-7$