Problem

In a certain school district, it was observed that $32 \%$ of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 119 out of 323 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the $\alpha=0.02$ level of significance.
What is the hypothesized population proportion for this test?
\[
p=
\]
(Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.)
Based on the statement of this problem, how many tails would this hypothesis test have?
one-tailed test
two-tailed test
Choose the correct pair of hypotheses for this situation:
\begin{tabular}{|l|c|c|c|c|c|c|c|c|c|c|c|c|c|}
\hline (A) & (B) & (C) & $\begin{array}{l}H_{0}: p=0.32 \\
H_{a}: p< 0.32\end{array}$ & $\begin{array}{l}H_{0}: p=0.32 \\
H_{a}: p \neq 0.32\end{array}$ & $\begin{array}{l}H_{0}: p=0.32 \\
H_{a}: p> 0.32\end{array}$ & (D) & (E) & (F) & $\begin{array}{l}H_{0}: p=0.368 \\
H_{a}: p< 0.368\end{array}$ & $\begin{array}{l}H_{0}: p=0.368 \\
H_{a}: p \neq 0.368\end{array}$ & $\begin{array}{l}H_{0}: p=0.368 \\
H_{a}: p> 0.368\end{array}$ \\
\hline
\end{tabular}
(A) (B) (C) (D) (E) $(\mathrm{F}) 0^{8}(\mathrm{~B}) \times$
Using the normal approximation for the binomial distribution (without the continuity correction), was is the test statistic for this sample based on the sample proportion?
$z=$
(Report answer as a decimal accurate to 3 decimal places.)
You are now ready to calculate the $P$-value for this sample.
$\mathrm{P}$-value $=$

Answer

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Answer

\(\boxed{p=0.32}\)

Steps

Step 1 :The hypothesized population proportion for this test is given as the proportion of students in the element schools who were classified as only children. This is the proportion we are testing against, so it is our hypothesized population proportion.

Step 2 :From the problem statement, we know that 32% of the students in the element schools were classified as only children. Therefore, the hypothesized population proportion for this test is \(p=0.32\).

Step 3 :\(\boxed{p=0.32}\)

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