Solve the quadratic equation by using the quadratic formula. (Enter your answers as a comma-separated list.
\[
2 x^{2}-7 x+4=0
\]

Step 1 ：Given the quadratic equation \(2x^{2}-7x+4=0\).

Step 2 ：The quadratic formula is given by \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).

Step 3 ：Here, the coefficients of the quadratic equation are \(a = 2\), \(b = -7\), and \(c = 4\).

Step 4 ：Substitute these values into the quadratic formula to find the solutions for \(x\).

Step 5 ：Calculate the discriminant \(D = b^2 - 4ac = 17\).

Step 6 ：Find the first solution \(sol1 = \frac{-(-7) + \sqrt{17}}{2*2} = 0.7192235935955849\).

Step 7 ：Find the second solution \(sol2 = \frac{-(-7) - \sqrt{17}}{2*2} = 2.7807764064044154\).

Step 8 ：Final Answer: The solutions to the quadratic equation are \(\boxed{0.7192235935955849, 2.7807764064044154}\)