Through (4,1) ; slope 3
Substituting m = 3 and b = -11 into the equation y = mx + b, we get the final equation of the line: \(\boxed{y = 3x - 11}\).
Step 1 :Given a point (4,1) and a slope of 3, we can substitute these values into the general form of a linear equation y = mx + b.
Step 2 :Substituting x = 4, y = 1, and m = 3, we get 1 = 3*4 + b.
Step 3 :Solving for b, we get b = -11.
Step 4 :Substituting m = 3 and b = -11 into the equation y = mx + b, we get the final equation of the line: \(\boxed{y = 3x - 11}\).