If int_{0}^{1} f(x) d x=-3 and int_{1}^{6} f(x) d x=-8, then int_{0}^{6}(-4-7 f(x)) d x=

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Step:1 ：We are given that (int_{0}^{1} f(x) d x=-3) and (int_{1}^{6} f(x) d x=-8).Step:2 ：We can add these two integrals to find the integral of f(x) from 0 to 6, which is (-3 + -8 = -11).Step:3 ：We are also given the integral of (-4-7f(x)) from 0 to 6. We can find this by integrating -4 from 0 to 6, which is (-4 * 6 = -24), and subtracting 7 times the integral of f(x) from 0 to 6, which is (7 * -11 = -77).Step:4 ：So, the integral of (-4-7f(x)) from 0 to 6 is (-24 - -77 = 53).Step:5 ：Final Answer: The integral of (-4-7f(x)) from 0 to 6 is (boxed{53}).

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Step: 1 ：We are given that (int_{0}^{1} f(x) d x=-3) and (int_{1}^{6} f(x) d x=-8).Step: 2 ：We can add these two integrals to find the integral of f(x) from 0 to 6, which is (-3 + -8 = -11).Step: 3 ：We are also given the integral of (-4-7f(x)) from 0 to 6. We can find this by integrating -4 from 0 to 6, which is (-4 * 6 = -24), and subtracting 7 times the integral of f(x) from 0 to 6, which is (7 * -11 = -77).Step: 4 ：So, the integral of (-4-7f(x)) from 0 to 6 is (-24 - -77 = 53).Step: 5 ：Final Answer: The integral of (-4-7f(x)) from 0 to 6 is (boxed{53}).

If $\int_{0}^{1} f(x) d x=-3$ and $\int_{1}^{6} f(x) d x=-8$, then $\int_{0}^{6}(-4-7 f(x)) d x=$

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