a) Cards are drawn from an ordinary deck and not replaced. Find the probability of drawing first a Jack and second a Queen.
Event $A=$
Event $\mathrm{B}=$
drawing first Jack
drawing second Queen
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P( drawing first Jack and second Queen $(\hat{\text { ) }}$ )
$P($ drawing first Jack and second Queen ( $)$
$P($ drawing first Jack and second Queen (2) )
Show work using fraction(s)
$=$
Write the answer as a decimal rounded to six decimal places $=$
Write the answer as a percent rounded to two decimal places $=$
$\%$

Step 1 ：The problem is asking for the probability of two dependent events: drawing a Jack first and then drawing a Queen. Since the cards are not replaced, the total number of cards decreases after the first draw, which affects the probability of the second draw.

Step 2 ：To solve this, we need to calculate the probability of each event separately and then multiply them together.

Step 3 ：The probability of drawing a Jack first is \(\frac{4}{52}\) (since there are 4 Jacks in a deck of 52 cards). After drawing a Jack, there are now 51 cards left in the deck. The probability of drawing a Queen next is \(\frac{4}{51}\) (since there are 4 Queens in the remaining 51 cards).

Step 4 ：So, the overall probability is \(\frac{4}{52} \times \frac{4}{51}\).

Step 5 ：The result from the calculation is the probability of drawing a Jack first and then a Queen from a deck of cards without replacement.

Step 6 ：Final Answer: The probability of drawing first a Jack and then a Queen from a deck of cards without replacement is approximately \(\boxed{0.006033}\).