Part B: Linear Relations [6 marks]
4. For the linear relation: $y=3 x+1$
a. Complete the table of values for $(x=-1,0,1,2,3)$. [2 marks]
\begin{tabular}{|l|l|}
\hline$x$ & $y$ \\
\hline & \\
\hline & \\
\hline & \\
\hline & \\
\hline & \\
\hline
\end{tabular}
b. Determine the rate of change (slope). [1 mark]

Step 1 ：Substitute the given x values into the equation y=3x+1 to find the corresponding y values.

Step 2 ：For x=-1, y=3*(-1)+1=-2

Step 3 ：For x=0, y=3*0+1=1

Step 4 ：For x=1, y=3*1+1=4

Step 5 ：For x=2, y=3*2+1=7

Step 6 ：For x=3, y=3*3+1=10

Step 7 ：The completed table of values for the given linear relation \(y=3x+1\) for the values of \(x\) as \(-1, 0, 1, 2, 3\) is: \begin{tabular}{|l|l|}\hline$x$ & $y$ \\ \hline-1 & -2 \\ \hline0 & 1 \\ \hline1 & 4 \\ \hline2 & 7 \\ \hline3 & 10 \\ \hline\end{tabular}

Step 8 ：The rate of change (slope) of the linear relation \(y=3x+1\) is 3, as it is the coefficient of \(x\) in the equation.