If a 185-Ib patient is prescribed $145 \mathrm{mg}$ of the cholesterol lowering drug Tricor daily, what dosage is the patient receiving in $\mathrm{mg} / \mathrm{kg}$ of his body weight?
$0.784 \mathrm{mg} / \mathrm{kg}$
$1.28 \mathrm{mg} / \mathrm{kg}$
$0.356 \mathrm{mg} / \mathrm{kg}$
$1.72 \mathrm{mg} / \mathrm{kg}$
$0.580 \mathrm{mg} / \mathrm{kg}$
Answer
Final Answer: The patient is receiving approximately \(\boxed{1.73 \, \text{mg/kg}}\) of his body weight in Tricor daily.
Step 1 ：First, we need to convert the patient's weight from pounds to kilograms, since the dosage is asked in mg/kg. We know that 1 pound is approximately 0.453592 kg. So, the patient's weight in kilograms is \(185 \times 0.453592 = 83.91452 \, \text{kg}\).
Step 2 ：Next, we calculate the dosage by dividing the amount of drug (in mg) by the patient's weight (in kg). So, the dosage is \(\frac{145}{83.91452} = 1.7279488698737717 \, \text{mg/kg}\).
Step 3 ：Final Answer: The patient is receiving approximately \(\boxed{1.73 \, \text{mg/kg}}\) of his body weight in Tricor daily.
