Suppose the data to the right represent the survival data for the a certain ship that sank. The males are adult males and the females are adult females. Complete parts (a) through (j).
$\begin{array}{lrrrr} & \text { Male } & \text { Female } & \text { Child } & \text { Total } \\ \text { Survived } & 243 & 396 & 79 & 718 \\ \text { "Died } & 1,099 & 72 & 53 & 1,224 \\ \text { Total } & 1,342 & 468 & 132 & 1,942\end{array}$
(a) If a passenger is selected at random, what is the probability that the passenger survived?
0.370 (Round to three decimal places as needed.)
(b) If a passenger is selected at random, what is the probability that the passenger was female?
0.241 (Round to three decimal places as needed.)
(c) If a passenger is selected at random, what is the probability that the passenger was female or a child?
(Round to three decimal places as needed.)
Answer
Rounding to three decimal places, the final answer is \(\boxed{0.309}\).
Step 1 ：Given the total number of passengers is 1942, the number of female passengers is 468, and the number of child passengers is 132.
Step 2 ：We need to find the probability that a passenger selected at random was either a female or a child.
Step 3 ：The probability of an event is calculated by dividing the number of ways the event can occur by the total number of outcomes.
Step 4 ：In this case, the event is a passenger being a female or a child, and the total number of outcomes is the total number of passengers.
Step 5 ：So, the probability of a passenger being a female or a child is \(\frac{468 + 132}{1942} = 0.30895983522142123\).
Step 6 ：Rounding to three decimal places, the final answer is \(\boxed{0.309}\).
