How many different simple random samples of size 5 can be obtained from a population whose size is 51 ?
The number of simple random samples which can be obtained is
(Type a whole number.)

Step 1 ：We are asked to find the number of ways to choose 5 items from a set of 51 items. This is a problem of combinations, which is given by the formula for combinations: \(C(n, k) = \frac{n!}{k!(n-k)!}\), where \(n\) is the total number of items, \(k\) is the number of items to choose, and '!' denotes factorial.

Step 2 ：Substitute \(n = 51\) and \(k = 5\) into the formula.

Step 3 ：Calculate the combinations: \(C(51, 5) = \frac{51!}{5!(51-5)!} = 2349060\).

Step 4 ：Final Answer: The number of different simple random samples of size 5 that can be obtained from a population whose size is 51 is \(\boxed{2349060}\).