5.4 .21
Part 2 of 2
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Suppose you just received a shipment of thirteen televisions. Two of the televisions are defective. If two televisions are randomly selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not work?
The probability that both televisions work is 0.705 . (Round to three decimal places as needed.)
The probability that at least one of the two televisions does not work is
(Round to three decimal places as needed.)

Step 1 ：The first part of the question has already been answered, so we only need to answer the second part. The probability that at least one of the two televisions does not work can be calculated by subtracting the probability that both televisions work from 1. The probability that both televisions work is given as 0.705.

Step 2 ：Let's denote the probability that both televisions work as \(prob\_both\_work\) and the probability that at least one television does not work as \(prob\_at\_least\_one\_doesnt\_work\).

Step 3 ：We know that \(prob\_both\_work = 0.705\).

Step 4 ：We can calculate \(prob\_at\_least\_one\_doesnt\_work\) by subtracting \(prob\_both\_work\) from 1, which gives us \(prob\_at\_least\_one\_doesnt\_work = 1 - prob\_both\_work = 1 - 0.705 = 0.295\).

Step 5 ：Final Answer: The probability that at least one of the two televisions does not work is \(\boxed{0.295}\).