Question 14
1 pts
You stand on a platform 20 meters high and throw a ball horizontally with an initial speed of $30 \mathrm{~m} / \mathrm{s}$. How far (in $\mathrm{m}$ ) from the bottdns of the platform will the ball hit the ground?

Step 1 ：This problem is a physics problem involving projectile motion. The horizontal distance covered by the ball when it hits the ground is called the range. The range of a projectile launched horizontally from a height with initial speed v is given by the formula: Range = v * sqrt(2h/g) where h is the height from which the ball is thrown and g is the acceleration due to gravity.

Step 2 ：In this case, the initial speed v = 30 m/s, the height h = 20 m, and the acceleration due to gravity g = 9.8 m/s^2.

Step 3 ：Substitute the given values into the formula: Range = 30 * sqrt(2*20/9.8)

Step 4 ：Solve the equation to find the range, which is approximately 60.61 meters.

Step 5 ：\(\boxed{60.61}\) meters is the final answer. The ball will hit the ground approximately 60.61 meters from the bottom of the platform.