Evaluate the function at the given value of the variable.
\[
f(x)=3 x^{2}+2 x-1
\]
a. $f(5)$
b. $f(-6)$
a. $f(5)=$
b. $f(-6)=$
Final Answer: \(a. f(5)=\boxed{84}\) \(b. f(-6)=\boxed{95}\)
Step 1 :Given the function \(f(x)=3 x^{2}+2 x-1\), we are asked to evaluate the function at \(x=5\) and \(x=-6\).
Step 2 :Substitute \(x=5\) into the function: \(f(5)=3(5)^{2}+2(5)-1\).
Step 3 :Simplify to get \(f(5)=75+10-1=84\).
Step 4 :Substitute \(x=-6\) into the function: \(f(-6)=3(-6)^{2}+2(-6)-1\).
Step 5 :Simplify to get \(f(-6)=108-12-1=95\).
Step 6 :Final Answer: \(a. f(5)=\boxed{84}\) \(b. f(-6)=\boxed{95}\)