Write the first four terms of the sequence $\left\{a_{n}\right\}_{n=1}^{\infty}$.
\[
a_{n}=\frac{(-1)^{n}}{6^{n}}
\]
\[
a_{1}=\square(\text { Simplify your answer. })
\]

Answer

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Answer

$\boxed{-\frac{1}{6}}$ is the first term of the sequence.

Steps

Step 1 ：Substitute $n=1$ into the formula for $a_n$.

Step 2 ：Calculate $a_n = \frac{(-1)^{1}}{6^{1}}$.

Step 3 ：Simplify to get $a_1 = -\frac{1}{6}$.

Step 4 ：$\boxed{-\frac{1}{6}}$ is the first term of the sequence.