Solve for \( x \) :
\[
2^{3}\left(\frac{3}{4}+x\right)+12=2
\]
x=-2
Step 1 :2^{3}(\frac{3}{4}+x)+12=2
Step 2 :8(\frac{3}{4}+x)+12=2
Step 3 :8\left(\frac{3+4x}{4}\right)+12=2
Step 4 :2(3+4x)+12=2
Step 5 :6+8x+12=2
Step 6 :8x+18=2
Step 7 :8x=-16
Step 8 :x=-2