Find the probability of $z$ occurring in the indicated region of the standard normal distribution.
Click here to view page 1 of the standard normal table
Click here to view page 2 of the standard normal table.
\[
P(0< z< 1.28)=
\]
(Round to four decimal places as needed.)

Step 1 ：We are given a standard normal distribution, which is a special case of the normal distribution where the mean is zero and the standard deviation is one. The z-score is a measure of how many standard deviations an element is from the mean.

Step 2 ：We are asked to find the probability that the z-score is between 0 and 1.28. This is equivalent to finding the area under the standard normal curve between these two values.

Step 3 ：We can find this probability by looking up the z-scores in the standard normal distribution table. The value in the table for z=1.28 gives the probability that z is less than or equal to 1.28.

Step 4 ：Since the total probability for z less than 0 is 0.5 (because the standard normal distribution is symmetric about zero), the probability that 0 < z < 1.28 is the probability that z < 1.28 minus the probability that z < 0.

Step 5 ：From the standard normal distribution table, we find that the probability that z is less than or equal to 1.28 is 0.8997.

Step 6 ：Subtracting the probability that z is less than 0 (0.5) from the probability that z is less than or equal to 1.28 (0.8997), we get 0.3997.

Step 7 ：Final Answer: The probability that \(0