A class has 34 students. In how many different ways can six students form a group for an activity? (Assume the order of the students is not important.)
There are different ways that the six students can form a group for an activity. (Type a whole number.)

Step 1 ：We are given a class of 34 students and we are asked to find out in how many different ways can six students form a group for an activity. The order of the students is not important.

Step 2 ：This is a combination problem. The formula for combinations is: \[C(n, k) = \frac{n!}{k!(n-k)!}\] where n is the total number of items, k is the number of items to choose, and '!' denotes factorial, which is the product of all positive integers up to that number.

Step 3 ：In this case, n = 34 (the total number of students) and k = 6 (the number of students to form a group).

Step 4 ：Substituting the given values into the formula, we get: \[C(34, 6) = \frac{34!}{6!(34-6)!}\]

Step 5 ：Solving the above expression, we find that there are 1,344,904 different ways that the six students can form a group for an activity.

Step 6 ：Final Answer: \(\boxed{1,344,904}\)