Problem

Determine whether the statement below is true or false. If it is false, rewrite it as a true statement.
\[
{ }_{7} \mathrm{C}_{5}={ }_{7} \mathrm{C}_{2}
\]
Choose the correct answer below.
A. This statement is false. A true statement is ${ }_{2} \mathrm{C}_{7}={ }_{5} \mathrm{C}_{7}$.
B. This statement is false. A true statement is ${ }_{7} \mathrm{C}_{5}={ }_{7} \mathrm{P}_{2}$.
C. This statement is true.
D. This statement is false. A true statement is $\mathrm{C}_{4}={ }_{7} \mathrm{C}_{2}$

Answer

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Answer

Final Answer: \(\boxed{{ }_{7} \mathrm{C}_{5}={ }_{7} \mathrm{C}_{2}}\) is a true statement.

Steps

Step 1 :The problem is asking whether the number of ways to choose 5 items from 7 is the same as the number of ways to choose 2 items from 7. This is a property of combinations, where choosing r items from n is the same as choosing (n-r) items from n.

Step 2 :To verify this, we need to calculate both sides of the equation and compare them.

Step 3 :Using the combination formula \( { }_{n} \mathrm{C}_{r} = \frac{n!}{r!(n-r)!} \), we can calculate the left side of the equation as \( { }_{7} \mathrm{C}_{5} = 21.0 \).

Step 4 :Similarly, we can calculate the right side of the equation as \( { }_{7} \mathrm{C}_{2} = 21.0 \).

Step 5 :Since both sides of the equation are equal, the statement is true.

Step 6 :Final Answer: \(\boxed{{ }_{7} \mathrm{C}_{5}={ }_{7} \mathrm{C}_{2}}\) is a true statement.

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