Problem

Use a standard normal distribution table to find the percentage of area above the standard normal curve that is specified.
Above $z=1.54$

Answer

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Answer

Therefore, the percentage of area above the standard normal curve for \(z=1.54\) is approximately \(\boxed{6.18\%}\).

Steps

Step 1 :Use a standard normal distribution table to find the percentage of area above the standard normal curve that is specified.

Step 2 :The standard normal distribution table gives us the area to the left of a given z-score. To find the area above a certain z-score, we need to subtract the area to the left of the z-score from 1.

Step 3 :For z = 1.54, the area to the left is approximately 0.9382.

Step 4 :Subtract this value from 1 to find the area above the z-score: 1 - 0.9382 = 0.0618.

Step 5 :Therefore, the percentage of area above the standard normal curve for \(z=1.54\) is approximately \(\boxed{6.18\%}\).

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