A frequency distribution is shown below. Complete parts (a) and (b).
The number of televisions per household in a small town
$\begin{array}{lcccc}\text { Televisions } & 0 & 1 & 2 & 3 \\ \text { Households } & 28 & 444 & 720 & 1410\end{array}$
(a) Use the frequency distribution to construct a probability distribution.
(Round to three decimal places as needed.)

Step 1 ：A frequency distribution is given as follows: the number of televisions per household in a small town is distributed as \(0\) televisions in \(28\) households, \(1\) television in \(444\) households, \(2\) televisions in \(720\) households, and \(3\) televisions in \(1410\) households.

Step 2 ：We are asked to use the frequency distribution to construct a probability distribution. The probability of an event is calculated by dividing the frequency of the event by the total frequency.

Step 3 ：The total frequency is the total number of households, which is the sum of all the households in the frequency distribution. So, the total number of households is \(28 + 444 + 720 + 1410 = 2602\) households.

Step 4 ：The probability of having \(0\) televisions is \(\frac{28}{2602} = 0.011\), the probability of having \(1\) television is \(\frac{444}{2602} = 0.171\), the probability of having \(2\) televisions is \(\frac{720}{2602} = 0.277\), and the probability of having \(3\) televisions is \(\frac{1410}{2602} = 0.542\).

Step 5 ：Final Answer: The probability distribution is \(\boxed{[0.011, 0.171, 0.277, 0.542]}\).