It has been determined that the of producirig $x$ units of a certain item is $6 x+860$. The demand function is given by $p(x)=50-0.5 x$. Step 1 of 2 : Find the revenue function.
\(\boxed{R(x) = 50x - 0.5x^2}\) is the final answer.
Step 1 :The cost of producing \(x\) units of a certain item is given by the function \(C(x) = 6x + 860\). The demand function is given by \(p(x) = 50 - 0.5x\).
Step 2 :The revenue function is the product of the price function and the quantity of items sold. In this case, the price function is \(p(x) = 50 - 0.5x\) and the quantity of items sold is \(x\).
Step 3 :Therefore, the revenue function \(R(x)\) can be calculated as \(R(x) = x * p(x)\).
Step 4 :Substituting the given price function into the revenue function, we get \(R(x) = x * (50 - 0.5x)\).
Step 5 :Simplifying the above expression, we get the final revenue function as \(R(x) = 50x - 0.5x^2\).
Step 6 :\(\boxed{R(x) = 50x - 0.5x^2}\) is the final answer.