Use the rules for sums of powers of integers to compute the sum.
\[
\sum_{k=6}^{23} k
\]

Step 1 ：Use the rules for sums of powers of integers to compute the sum \(\sum_{k=6}^{23} k\)

Step 2 ：The sum of integers from 1 to n is given by the formula \(\frac{n*(n+1)}{2}\). To find the sum from k to n, we can subtract the sum from 1 to k-1 from the sum from 1 to n. In this case, we need to find the sum from 6 to 23, so we can subtract the sum from 1 to 5 from the sum from 1 to 23.

Step 3 ：Calculate the sum from 1 to 23: \(\frac{23*(23+1)}{2} = 276\)

Step 4 ：Calculate the sum from 1 to 5: \(\frac{5*(5+1)}{2} = 15\)

Step 5 ：Subtract the sum from 1 to 5 from the sum from 1 to 23 to get the sum from 6 to 23: \(276 - 15 = 261\)

Step 6 ：Final Answer: The sum of integers from 6 to 23 is \(\boxed{261}\)