Find $f_{x x}, f_{x y}, f_{y x}$, and $f_{y y}$ for the following function. (Remember, $f_{y x}$ means to differentiate with respect to $y$ and then with respect to $x$.)
\[
f(x, y)=2 x+3 y
\]

Step 1 ：The function given is \(f(x, y)=2x+3y\).

Step 2 ：First, we find the first order partial derivatives, \(f_x\) and \(f_y\), which are the derivatives of the function with respect to \(x\) and \(y\) respectively.

Step 3 ：The derivative of \(f\) with respect to \(x\) is \(f_x = 2\).

Step 4 ：The derivative of \(f\) with respect to \(y\) is \(f_y = 3\).

Step 5 ：Next, we find the second order partial derivatives, \(f_{xx}\), \(f_{xy}\), \(f_{yx}\), and \(f_{yy}\). These are the derivatives of the first order partial derivatives.

Step 6 ：To find \(f_{xx}\), we differentiate \(f_x\) with respect to \(x\), which gives \(f_{xx} = 0\).

Step 7 ：To find \(f_{xy}\), we differentiate \(f_x\) with respect to \(y\), which gives \(f_{xy} = 0\).

Step 8 ：To find \(f_{yx}\), we differentiate \(f_y\) with respect to \(x\), which gives \(f_{yx} = 0\).

Step 9 ：To find \(f_{yy}\), we differentiate \(f_y\) with respect to \(y\), which gives \(f_{yy} = 0\).

Step 10 ：Final Answer: The second order partial derivatives of the function \(f(x, y)=2x+3y\) are \(\boxed{f_{xx}=0, f_{xy}=0, f_{yx}=0, f_{yy}=0}\).