Problem

If $P(E)=0.26$, then what are the odds against $E$ ?
The odds against $E$ are to (Simplify your answers.)

Answer

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Answer

So, the odds against E are approximately \(\boxed{2.85}\) to 1.

Steps

Step 1 ：Given that the probability of event E, denoted as P(E), is 0.26.

Step 2 ：The probability that event E will not occur, denoted as P(not E), is calculated as 1 - P(E) = 1 - 0.26 = 0.74.

Step 3 ：The odds against E are the ratio of the probability that the event will not occur to the probability that the event will occur. Therefore, the odds against E are calculated as P(not E) : P(E) = 0.74 : 0.26.

Step 4 ：Simplifying this ratio gives approximately 2.85 to 1.

Step 5 ：So, the odds against E are approximately \(\boxed{2.85}\) to 1.

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