We are flipping three coins. Outcomes in the sample space are represented by strings of $\mathrm{Hs}$ and Ts such as TTH and HHT.
c. What is the probability that there are more tails than heads?
Answer
Final Answer: The probability that there are more tails than heads when flipping three coins is \(\boxed{0.5}\).
Step 1 ：We are flipping three coins. Outcomes in the sample space are represented by strings of Hs and Ts such as TTH and HHT.
Step 2 ：The sample space for flipping three coins consists of 8 outcomes: HHH, HHT, HTH, HTT, THH, THT, TTH, TTT.
Step 3 ：Out of these, the outcomes with more tails than heads are HTT, THT, TTH, TTT.
Step 4 ：So, the probability of getting more tails than heads is the number of favorable outcomes divided by the total number of outcomes.
Step 5 ：\(\text{total outcomes} = 8\)
Step 6 ：\(\text{favorable outcomes} = 4\)
Step 7 ：\(\text{probability} = \frac{\text{favorable outcomes}}{\text{total outcomes}} = \frac{4}{8} = 0.5\)
Step 8 ：Final Answer: The probability that there are more tails than heads when flipping three coins is \(\boxed{0.5}\).
