Find the mean, variance, and standard deviation of the binomial distribution with the given values of $n$ and $p$.
\[
n=127, p=0.78
\]
The mean, $\mu$, is (Round to the nearest tenth as needed.)
So, the mean, \(\mu\), is \(\boxed{99.1}\).
Step 1 :Given values are n = 127 and p = 0.78.
Step 2 :The mean of a binomial distribution is calculated as \(n*p\).
Step 3 :Substitute the given values into the formula: mean = 127 * 0.78.
Step 4 :Calculate the mean to get approximately 99.06.
Step 5 :Round the mean to the nearest tenth to get 99.1.
Step 6 :So, the mean, \(\mu\), is \(\boxed{99.1}\).