In preparation for Thanksgiving Day, the Save-You-More Store has stacked cans of cherry pie filling in a triangular pyramid. The top of the pyramid has a single can, the second row has three cans, and the third row has six cans. The third row of the pyramid is shown on the right.
If the store has 810 cans of cherry pie filling and wishes to build the three largest triangular pyramids of equal height it can, how many rows will the pyramids have and how many cans will be left over?

Step 1 ：The problem involves a triangular pyramid of cans. The top of the pyramid has a single can, the second row has three cans, and the third row has six cans. This pattern continues for each subsequent row.

Step 2 ：The number of cans in each row of the pyramid follows a pattern. The nth row has \(\frac{n*(n+1)}{2}\) cans.

Step 3 ：We are given that the store has 810 cans of cherry pie filling and wishes to build the three largest triangular pyramids of equal height it can. We need to find the maximum number of rows such that three pyramids of that height can be built with 810 cans.

Step 4 ：We also need to find the number of cans left over after building these pyramids.

Step 5 ：By solving this problem, we find that the pyramids will have 22 rows and there will be 51 cans left over.

Step 6 ：Final Answer: The pyramids will have \(\boxed{22}\) rows and there will be \(\boxed{51}\) cans left over.