Find the slope and $y$-intercept of the line with equation $3 x-y=5$. Then graph the line.
\(\boxed{\text{The slope of the line is } 3 \text{ and the } y\text{-intercept is } -5}\)
Step 1 :Rearrange the equation $3x - y = 5$ into slope-intercept form $y = mx + b$, where $m$ is the slope and $b$ is the $y$-intercept.
Step 2 :The equation becomes $y = 3x - 5$
Step 3 :From the equation, we can see that the slope $m$ is $3$ and the $y$-intercept $b$ is $-5$
Step 4 :Plot the line using these values. The line passes through the point $(0, -5)$ and rises $3$ units for every $1$ unit it moves to the right.
Step 5 :\(\boxed{\text{The slope of the line is } 3 \text{ and the } y\text{-intercept is } -5}\)