Problem

\( \mathrm{ABC} \) is a right angled triangle at \( \mathrm{B}, \overline{B D} \perp \overline{A C} \) then \( (B D)^{2}=A D \times \ldots \)

Answer

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Answer

\( (BD)^{2}=AD \times DC \)

Steps

Step 1 :\( (AC)^{2}=(AB)^{2}+(BC)^{2} \)

Step 2 :\( (AD)^{2}+(BD)^{2}=(DC)^{2}+(BD)^{2} \)

Step 3 :\( (BD)^{2}=AD \times DC \)

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