A−(x+3)2=−4x−15
Final Answer: x=−A+7−1 and x=A+7−1
Step 1 :Expand the equation: A−(x+3)2=−4x−15⇒A−x2−6x−9=−4x−15
Step 2 :Isolate x: x2+2x−(A+6)=0
Step 3 :Final Answer: x=−A+7−1 and x=A+7−1