1. In an arithmetic series
- the first term is 16
- the 21 st term is 24
(a) Find the common difference of the series.
(b) Hence find the sum of the first 500 terms of the series.
\(\boxed{107800}\)
Step 1 :\(a_1 = 16\)
Step 2 :\(a_{21} = 24\)
Step 3 :\(a_n = a_1 + (n-1)d\)
Step 4 :\(24 = 16 + (21-1)d\)
Step 5 :\(8 = 20d\)
Step 6 :\(d = \frac{8}{20} = \frac{2}{5}\)
Step 7 :\(S_n = \frac{n}{2}(a_1 + a_n)\)
Step 8 :\(S_{500} = \frac{500}{2}(16 + a_{500})\)
Step 9 :\(a_{500} = 16 + (500-1)\frac{2}{5}\)
Step 10 :\(a_{500} = 16 + 499\frac{2}{5}\)
Step 11 :\(a_{500} = 16 + 998\frac{2}{5}\)
Step 12 :\(a_{500} = 16 + 399.2\)
Step 13 :\(a_{500} = 415.2\)
Step 14 :\(S_{500} = \frac{500}{2}(16 + 415.2)\)
Step 15 :\(S_{500} = 250(431.2)\)
Step 16 :\(S_{500} = 107800\)
Step 17 :\(\boxed{107800}\)