begin{aligned} x-3 y+2 z & =17 x-y+z & =8 y+z & =3end{aligned}

Question

begin{aligned} x-3 y+2 z & =17  x-y+z & =8  y+z & =3end{aligned}

Accepted Answer

Step:1 ：We are given a system of linear equations: (x-3y+2z = 17), (x-y+z = 8), and (y+z = 3).Step:2 ：We can represent this system in matrix form as follows: [A = begin{bmatrix} 1 & -3 & 2  1 & -1 & 1  0 & 1 & 1 end{bmatrix}, b = begin{bmatrix} 17  8  3 end{bmatrix}]Step:3 ：We solve this system to find the values of x, y, and z.Step:4 ：The solution to the system of equations is (x = 1), (y = -2), and (z = 5).Step:5 ：Final Answer: (boxed{x = 1, y = -2, z = 5})

Answer

Step: 1 ：We are given a system of linear equations: (x-3y+2z = 17), (x-y+z = 8), and (y+z = 3).Step: 2 ：We can represent this system in matrix form as follows: [A = begin{bmatrix} 1 & -3 & 2  1 & -1 & 1  0 & 1 & 1 end{bmatrix}, b = begin{bmatrix} 17  8  3 end{bmatrix}]Step: 3 ：We solve this system to find the values of x, y, and z.Step: 4 ：The solution to the system of equations is (x = 1), (y = -2), and (z = 5).Step: 5 ：Final Answer: (boxed{x = 1, y = -2, z = 5})

$\begin{aligned} x-3 y+2 z & =17 \\ x-y+z & =8 \\ y+z & =3\end{aligned}$

Answer

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