6. Given: $\overline{A B} \cong \overline{C B}, \overline{A D} \cong \overline{C D}$ Prove : $\angle B A D \cong \angle B C D$
Statement
1. $\overline{A B} \cong \overline{C B}, \overline{A D} \cong \overline{C D}$
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1. Given
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Answer

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Answer

$\boxed{\angle BAD \cong \angle BCD}$

Steps

Step 1 ：Given: $\overline{AB} \cong \overline{CB}$, $\overline{AD} \cong \overline{CD}$

Step 2 ：Since $\overline{AB} \cong \overline{CB}$ and $\overline{AD} \cong \overline{CD}$, we can use the Side-Side-Side (SSS) congruence theorem to prove that $\triangle ABD \cong \triangle CBD$

Step 3 ：Therefore, $\angle BAD \cong \angle BCD$

Step 4 ：$\boxed{\angle BAD \cong \angle BCD}$

6. Given: $\overline{A B} \cong \overline{C B}, \overline{A D} \cong \overline{C D}$ Prove : $\angle B A D \cong \angle B C D$Statement1. $\overline{A B} \cong \overline{C B}, \overline{A D} \cong \overline{C D}$2.3.4.1. Given2.3.4.

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6. Given: $\overline{A B} \cong \overline{C B}, \overline{A D} \cong \overline{C D}$ Prove : $\angle B A D \cong \angle B C D$
Statement
1. $\overline{A B} \cong \overline{C B}, \overline{A D} \cong \overline{C D}$
2.
3.
4.
1. Given
2.
3.
4.