The outside of a picture frame has a length which is $3 \mathrm{~cm}$ more than width. The area enclosed by the outside of the picture frame is $88 \mathrm{square} \mathrm{cm}$. Find the width of the outside of the picture frame.

Step 1 ：We are given that the length of the picture frame is 3 cm more than the width. Let's denote the width as \(w\) cm. Therefore, the length is \(w + 3\) cm.

Step 2 ：We are also given that the area enclosed by the outside of the picture frame is 88 square cm. The area of a rectangle is calculated by multiplying its length by its width. Therefore, we can set up the following equation: \(w * (w + 3) = 88\).

Step 3 ：Solving this equation gives us two possible solutions for \(w\): -11 and 8.

Step 4 ：However, since the width of a picture frame cannot be negative, we discard -11 as a possible solution.

Step 5 ：So, the width of the picture frame is 8 cm.

Step 6 ：Final Answer: The width of the outside of the picture frame is \(\boxed{8}\) cm.