Problem

\[
\frac{(2 x-3)}{5}+\frac{(4 x-1)}{10}=1
\]
Salve for \( x \)

Answer

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Hide Steps

Answer

\[ x=\frac{17}{8} \]

Steps

Step 1 ：\[ 2( \frac{(2x-3)}{5}+\frac{(4x-1)}{10} ) = 2(1) \]

Step 2 ：\[ \frac{(4x-6)}{5}+\frac{(4x-1)}{5}=2 \]

Step 3 ：\[ \frac{(8x-7)}{5}=2 \]

Step 4 ：\[ x=\frac{17}{8} \]

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