Problem

QUESTION 7.2
How do I know a matrix is Invertible Choose one $\cdot 4$ points Why is $A=\left(\begin{array}{ll}1 & 4 \\ 1 & 3\end{array}\right)$ invertible?
Because $\operatorname{det}(A)=0$
Because $\operatorname{det}(A) \neq 0$
Because $A=0$

Answer

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Answer

\(\boxed{\text{Therefore, the matrix } A=\left(\begin{array}{ll}1 & 4 \\ 1 & 3\end{array}\right) \text{ is invertible because its determinant is not equal to zero, i.e., } \operatorname{det}(A) \neq 0\}.\)

Steps

Step 1 :The determinant of a matrix is a special number that can be calculated from a square matrix. A Matrix is Invertible if and only if its determinant is not equal to zero.

Step 2 :To find out if the given matrix A is invertible, we need to calculate its determinant and check if it is not equal to zero.

Step 3 :The given matrix A is \(A=\left(\begin{array}{ll}1 & 4 \\ 1 & 3\end{array}\right)\).

Step 4 :Calculate the determinant of matrix A, \(\operatorname{det}(A)\).

Step 5 :The determinant of matrix A is -1, which is not equal to zero.

Step 6 :\(\boxed{\text{Therefore, the matrix } A=\left(\begin{array}{ll}1 & 4 \\ 1 & 3\end{array}\right) \text{ is invertible because its determinant is not equal to zero, i.e., } \operatorname{det}(A) \neq 0\}.\)

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