What is the numerator in the sum?
\[
\begin{array}{l}
2(x+1)(x-2)(x-4)+3(x+1)(x-2)(x-4) \\
2(x-2)(x-4)+3(x+1)(x-4) \\
2(x-2)+3(x+1)
\end{array}
\]

Answer

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Answer

Final Answer: The sum of the expressions is \(\boxed{5x + 5(x - 4)(x - 2)(x + 1) - 1}\)

Steps

Step 1 ：Simplify each expression individually: \(expr1 = 2(x - 4)(x - 2)(x + 1)\), \(expr2 = 3(x - 4)(x - 2)(x + 1)\), \(expr3 = 5x - 1\)

Step 2 ：Add the simplified expressions together: \(sum\_expr = 5x + 5(x - 4)(x - 2)(x + 1) - 1\)

Step 3 ：Final Answer: The sum of the expressions is \(\boxed{5x + 5(x - 4)(x - 2)(x + 1) - 1}\)