Problem

\[
\left[\begin{array}{rrrr}
-3 & 6 & -1 & -10 \\
2 & 4 & 1 & -25 \\
-2 & -6 & -5 & 29
\end{array}\right]
\]
Equation for row 1:
Equation for row 2:
Equation for row 3:

Answer

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Answer

Row 3: \(\boxed{-2x - 6y - 5z = 29}\)

Steps

Step 1 :The given matrix represents a system of linear equations. Each row in the matrix corresponds to one equation. The coefficients in each row correspond to the coefficients of the variables in the equation, and the last column corresponds to the constants on the right side of the equation.

Step 2 :For example, the first row [-3, 6, -1, -10] represents the equation \(-3x + 6y - z = -10\). We can apply this logic to each row to get the corresponding equation.

Step 3 :The equations for each row are as follows:

Step 4 :Row 1: \(\boxed{-3x + 6y - z = -10}\)

Step 5 :Row 2: \(\boxed{2x + 4y + z = -25}\)

Step 6 :Row 3: \(\boxed{-2x - 6y - 5z = 29}\)

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