left{begin{array}{l}4 x+6 y-6 z=36 2 x+y-2 z=13 2 x+3 y-2 z=15end{array}right.

Question

left{begin{array}{l}4 x+6 y-6 z=36  2 x+y-2 z=13  2 x+3 y-2 z=15end{array}right.

Accepted Answer

Step:1 ：We are given the system of linear equations: [begin{cases} 4x+6y-6z=36  2x+y-2z=13  2x+3y-2z=15 end{cases}]Step:2 ：We can represent this system in matrix form as: [A = begin{bmatrix} 4 & 6 & -6  2 & 1 & -2  2 & 3 & -2 end{bmatrix}, b = begin{bmatrix} 36  13  15 end{bmatrix}]Step:3 ：We solve this system to find the values of x, y, and z.Step:4 ：The solution to the system of equations is: [x = 3, y = 1, z = -3]Step:5 ：These values satisfy all three equations.Step:6 ：Final Answer: (boxed{x = 3, y = 1, z = -3})

Answer

Step: 1 ：We are given the system of linear equations: [begin{cases} 4x+6y-6z=36  2x+y-2z=13  2x+3y-2z=15 end{cases}]Step: 2 ：We can represent this system in matrix form as: [A = begin{bmatrix} 4 & 6 & -6  2 & 1 & -2  2 & 3 & -2 end{bmatrix}, b = begin{bmatrix} 36  13  15 end{bmatrix}]Step: 3 ：We solve this system to find the values of x, y, and z.Step: 4 ：The solution to the system of equations is: [x = 3, y = 1, z = -3]Step: 5 ：These values satisfy all three equations.Step: 6 ：Final Answer: (boxed{x = 3, y = 1, z = -3})

$\left\{\begin{array}{l}4 x+6 y-6 z=36 \\ 2 x+y-2 z=13 \\ 2 x+3 y-2 z=15\end{array}\right.$

Answer

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