The logistic growth function $\mathrm{P}(\mathrm{x})=\frac{90}{1+271 e^{-0.122 x}}$ models the percentage, $\mathrm{P}(\mathrm{x})$, of Americans who are $\mathrm{x}$ years old and have some coronary heart disease. Use this function to find the the percentage of 41-year olds who have some coronary heart disease.
What is the percentage of 41 -year olds with some coronary heart disease?
$\%$ (Round to one decimal place.)
Answer
So, the percentage of 41-year olds who have some coronary heart disease is approximately \(\boxed{31.9\%}\).
Step 1 ：The logistic growth function \(P(x)=\frac{90}{1+271 e^{-0.122 x}}\) models the percentage, \(P(x)\), of Americans who are \(x\) years old and have some coronary heart disease.
Step 2 ：We are asked to find the percentage of 41-year olds who have some coronary heart disease. This can be found by substituting \(x=41\) into the logistic growth function \(P(x)\) and calculating the result.
Step 3 ：After calculation, we find that the percentage is approximately 31.9%.
Step 4 ：So, the percentage of 41-year olds who have some coronary heart disease is approximately \(\boxed{31.9\%}\).
